Hi Karma, I hope you can digitize it and climb the forum I think it should be done if not someone will challenge us and say that it is not done, but everything you have referring to the heavy mercedes especially the OM 352 Welcome. Last send me a private MP message and we see how we get. Cordial greetings
how to relate the differential correctly
by AngelDerelew
the topic that I want to deal with and I hope you are interested, it is like relating a differential and knowing the almost exact speed only with the use of a tachometer (vuelta account). It all starts telling the teeth of the pinion and the crown that we have installed in our vehicle, in the example that I present is that of a Mercedes Benz 1114 with 900/20 roller and with a relationship that I think is the optima 39/8 or 39 teeth in the crown and 8 in the pinion for a Mercedes 1114 that is used as an motorhome or collective of medium or long distance.
To continue, after having obtained the data of the crown and pinion ratio that we have installed, we must divide 39/8 those that give us a result of 4.87 This result indicates the amount of turns or revolutions that the aforementioned pinion needs to complete a complete turn of the crown, which would give us in this case that our pinion needs to turn 4.87 turns to complete the complete turn of the crown. The other important fact that we need is the tire footprint that we have installed in this case, remember that it is a 900/20 that after measured the result that in a complete turn travels approximately 3.10 meters, according to the mark of the same this route can be modified in + - 5 cm which does not significantly modify our final result. Finally, the accounts to be performed are the following, taking into account that the aforementioned calculation is for vehicles that in its last march in this case 5th is of a 1/1 ratio, that is, each motor lap of a return at the cashier outlet, (that is, it does not possess overwhelon).
2000 rpm % 4.87 = 410.6 rpm/min x 3.10 mts = 1272 mts/min x 60 min/hour = 76.37 km/hour
2300 rpm % 4.87 = 472.2 rpm/min x 3.10 mts = 1463 mts/min x 60 min/hour = 87.78 km/hour
2600 rpm % 4.87 = 533.8 rpm/min x 3 Mts = 1654 mts/min x 60 min/hour = 99.24 km/hour
These are some examples taking into account that Mercedes 1114 has its original pump cut in 2800 rpm, and being everything in order with little wind the consumption should be around in a regime between 2000 and 2500 rpm of 17 to 20 liters every 100 km Let me know.
By AngelDerelew